Thursday, September 12, 2013

Math Chap 5 Portfolio

Chapter 5 Portfolio Chapter 5 5.1 pg. 321For Discussion 1. Linear Functions that argon non-constant argon will of all time be maven-to-one. A non-constant disceptationar move, f (x) = mx + b, where m is the slope and b is the intercept. y = mx + b. So, (y - b) / m = x = f^(-1) (y). (There is an Inverse) , so the function is 1 to 1. 2. The odd-degree poly Sometimes be one to one. an odd degree function may withdraw an even function within it. EX: x^3 -2x^2 +x -1 = y Which in this case it is incomplete odd nor even. Also may tumble horizontal trace test. 3. Even degree cant pretend an one to one because it will produce a pair of variant numbers that return to the same function prise and wont crystallize the horizontal line test pg. 327#30, 31, 106 30. Range of f =_f^-1_.........Domain of f = __f^-1__. 31.Point (b,a) lies on the chart __f^-1__ because orient (a, b) reflects graph f and (b,a) graph __(f^-1)__. 106.Unknow n 5.2 pg. 331Why do we curtail exponential function functions to a invertebrate foot that is non-negative and not 1? The reasons for the restrictions argon because. If a?0, then when you plagiarise it to a rational power, you may not get a real number. Ex: If a=-2, then (-2)0.5 = sqrt(-2) which isnt real. If a=1, the value of f(x) is 1. Which is not one-to-one.
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pg. 335What form essential we have the equation in to solve Type 1 exponential equations? You have to have (some pedestal) to (some power) = (the same base) to (some other power), where you specify the two powers pair to apiece other, and solve the equation. For example: take in 101x = 104 . 1 x = 4 ..1 4 = x .3 = x pg. 337Is ! e a variable or a number? Explain. e is an number , approximately equal to 2.71828, that is the base of the natural logarithm. 5.3 pg. 342What is a logarithm and how does it relate to exponential equations? Logarithms are the opponent of exponentials just as subtraction is the opposite of addendum and division is the opposite of...If you want to get a unspoiled essay, order it on our website: OrderEssay.net

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